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authorChris Sherlock <chris.sherlock79@gmail.com>2018-01-21 04:48:50 +1100
committerStephan Bergmann <sbergman@redhat.com>2018-02-05 09:00:54 +0100
commit01e470f0ab49e458c57b0f28636a517b2bfb1b4a (patch)
treee153e55125b3d5682e60425b80568c5e03a3695a /drawinglayer
parent79517c0471aff4abf336bd81834bd28732dad67f (diff)
vcl: remove BitmapColor Color() operator
BitmapColor has a Color() operator. However, this is confusing and tends to hide that the two classes aren't the same. I have converted this to GetColor(). Change-Id: I0be2dcb3fc420e7be9c8d04330e7a3fe69a5412a Reviewed-on: https://gerrit.libreoffice.org/48245 Reviewed-by: Stephan Bergmann <sbergman@redhat.com> Tested-by: Stephan Bergmann <sbergman@redhat.com>
Diffstat (limited to 'drawinglayer')
-rw-r--r--drawinglayer/source/texture/texture3d.cxx2
1 files changed, 1 insertions, 1 deletions
diff --git a/drawinglayer/source/texture/texture3d.cxx b/drawinglayer/source/texture/texture3d.cxx
index 069759533cd5..fc8750199c8f 100644
--- a/drawinglayer/source/texture/texture3d.cxx
+++ b/drawinglayer/source/texture/texture3d.cxx
@@ -122,7 +122,7 @@ namespace drawinglayer
{
const BitmapColor aBitmapColor(mpReadBitmap->GetColor(rY, rX));
- if(maBitmapEx.GetTransparentColor() == aBitmapColor.operator Color())
+ if(maBitmapEx.GetTransparentColor() == aBitmapColor.GetColor())
{
return 255;
}