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authorpragat-pandya <pragat.pandya@gmail.com>2022-03-29 16:25:15 +0530
committerHossein <hossein@libreoffice.org>2022-03-31 13:51:34 +0200
commita31aadb1ef7dfdd4ae76a15707ab51a82c95d868 (patch)
tree0cf5626a67b7c3a18b546c3e9d4d2c96b62dfbbf /dbaccess
parent9f041e7678521074b09b20f4088996c86bea5cd0 (diff)
tdf#147906 Use std::hypot for Pythagorean addition
Change-Id: I38166d36e9e8518ab86ded7ab630a35f3a0c39d7 Reviewed-on: https://gerrit.libreoffice.org/c/core/+/132268 Tested-by: Jenkins Reviewed-by: Hossein <hossein@libreoffice.org>
Diffstat (limited to 'dbaccess')
-rw-r--r--dbaccess/source/ui/querydesign/ConnectionLine.cxx2
1 files changed, 1 insertions, 1 deletions
diff --git a/dbaccess/source/ui/querydesign/ConnectionLine.cxx b/dbaccess/source/ui/querydesign/ConnectionLine.cxx
index 96086d60b682..77a67004e995 100644
--- a/dbaccess/source/ui/querydesign/ConnectionLine.cxx
+++ b/dbaccess/source/ui/querydesign/ConnectionLine.cxx
@@ -307,7 +307,7 @@ static double dist_Euklid(const Point &p1, const Point& p2,const Point& pM, Poin
{
Point v(p2 - p1);
Point w(pM - p1);
- double a = sqrt(static_cast<double>(v.X()*v.X() + v.Y()*v.Y()));
+ double a = std::hypot(v.X(), v.Y());
double l = (v.X() * w.Y() - v.Y() * w.X()) / a;
double a2 = w.X()*v.X()+w.Y()*v.Y();
a = a2 / (a * a);