diff options
| author | Michael Stahl <mstahl@redhat.com> | 2014-07-01 17:48:28 +0200 |
|---|---|---|
| committer | Michael Stahl <mstahl@redhat.com> | 2014-07-01 18:01:06 +0200 |
| commit | d51f53fedb8cd68b1b3122c7199c4ea2d3a6980f (patch) | |
| tree | 8b2487f1fc31acac79757c4a8a1d1eb7834b3e52 | |
| parent | 63cd667ccb35325a973cf4f98c5e1bf9db92b9b4 (diff) | |
fdo#80014: vcl: fix drawing of linear gradients
There is an off-by-one error in OutputDevice::ImplDrawLinearGradient()
that causes the bottom line to remain black.
(regression from 04d937c1ec36c2d9fa8c90604c81a37d30e97da6)
Change-Id: I33948ec8065e446a9ec7efeab5e506c93fa2e9e8
| -rw-r--r-- | vcl/source/outdev/gradient.cxx | 2 |
1 files changed, 1 insertions, 1 deletions
diff --git a/vcl/source/outdev/gradient.cxx b/vcl/source/outdev/gradient.cxx index 7a4a3c50a946..1f2a26c74b36 100644 --- a/vcl/source/outdev/gradient.cxx +++ b/vcl/source/outdev/gradient.cxx @@ -320,7 +320,7 @@ void OutputDevice::DrawLinearGradient( const Rectangle& rRect, // Polygon for this color step aRect.Top() = (long)( fGradientLine + ((double) i) * fScanInc ); - aRect.Bottom() = (long)( fGradientLine + ( ((double) i) + 1.0 ) * fScanInc + fScanInc*.1 ); + aRect.Bottom() = (long)( fGradientLine + ( ((double) i) + 1.0 ) * fScanInc ); aPoly[0] = aRect.TopLeft(); aPoly[1] = aRect.TopRight(); aPoly[2] = aRect.BottomRight(); |